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Homework for Chapter 8 of 《Operating Systems: Three Easy Pieces》: MLFQ Scheduling

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    • Select Homework for Chapter 8 of 《Operating Systems: Three Easy Pieces》: MLFQ Scheduling
    1

    root@C202511211157657:~# python3 mlfq.py -j 2 -M 0 -m 4 -n 2 -q 1
Here is the list of inputs:
OPTIONS jobs 2
OPTIONS queues 2
OPTIONS allotments for queue  1 is   1
OPTIONS quantum length for queue  1 is   1
OPTIONS allotments for queue  0 is   1
OPTIONS quantum length for queue  0 is   1
OPTIONS boost 0
OPTIONS ioTime 5
OPTIONS stayAfterIO False
OPTIONS iobump False


For each job, three defining characteristics are given:
  startTime : at what time does the job enter the system
  runTime   : the total CPU time needed by the job to finish
  ioFreq    : every ioFreq time units, the job issues an I/O
              (the I/O takes ioTime units to complete)

Job List:
  Job  0: startTime   0 - runTime   3 - ioFreq   0
  Job  1: startTime   0 - runTime   2 - ioFreq   0

Compute the execution trace for the given workloads.
If you would like, also compute the response and turnaround
times for each of the jobs.

Use the -c flag to get the exact results when you are finished.

    So I am trying to make this work easier by adjusting all the arguments as precise as possible.
    For This one, job 0 will go to queue 1 but will soon drop to queue 0 since it would use out its allotment.
    So it would be like:
    START JOB0
    START JOB1
    Run JOB 0 at PRIORITY 1
    Run JOB 1 at PRIORITY 0
    Run JOB 1 at PRIORITY 0
    Run JOB 0 at PRIORITY 0
    Run JOB 0 at PRIORITY 0

    Job StartTime Response Turnaround
    0 0 0 5
    1 0 1 4

    Actually:

    Execution Trace:

[ time 0 ] JOB BEGINS by JOB 0
[ time 0 ] JOB BEGINS by JOB 1
[ time 0 ] Run JOB 0 at PRIORITY 1 [ TICKS 0 ALLOT 1 TIME 2 (of 3) ]
[ time 1 ] Run JOB 1 at PRIORITY 1 [ TICKS 0 ALLOT 1 TIME 1 (of 2) ]
[ time 2 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 1 (of 3) ]
[ time 3 ] Run JOB 1 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 0 (of 2) ]
[ time 4 ] FINISHED JOB 1
[ time 4 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 0 (of 3) ]
[ time 5 ] FINISHED JOB 0

Final statistics:
  Job  0: startTime   0 - response   0 - turnaround   5
  Job  1: startTime   0 - response   1 - turnaround   4

  Avg  1: startTime n/a - response 0.50 - turnaround 4.50

    I made a mistake that all jobs should start with the highest priority.
    Let’s go on for the next generated problem:

    root@C202511211157657:~# python3 mlfq.py -j 2 -M 0 -m 8 -n 2 -q 2 -s 3
Here is the list of inputs:
OPTIONS jobs 2
OPTIONS queues 2
OPTIONS allotments for queue  1 is   1
OPTIONS quantum length for queue  1 is   2
OPTIONS allotments for queue  0 is   1
OPTIONS quantum length for queue  0 is   2
OPTIONS boost 0
OPTIONS ioTime 5
OPTIONS stayAfterIO False
OPTIONS iobump False


For each job, three defining characteristics are given:
  startTime : at what time does the job enter the system
  runTime   : the total CPU time needed by the job to finish
  ioFreq    : every ioFreq time units, the job issues an I/O
              (the I/O takes ioTime units to complete)

Job List:
  Job  0: startTime   0 - runTime   2 - ioFreq   0
  Job  1: startTime   0 - runTime   3 - ioFreq   0

Compute the execution trace for the given workloads.
If you would like, also compute the response and turnaround
times for each of the jobs.

Use the -c flag to get the exact results when you are finished.

    It would be like:
    [ time 0 ] JOB BEGINS by JOB 0
    [ time 0 ] JOB BEGINS by JOB 1
    [ time 0 ] Run JOB 0 at PRIORITY 1 [ TICKS 0 ALLOT 1 TIME 1 (of 2) ]
    [ time 1 ] Run JOB 1 at PRIORITY 1 [ TICKS 0 ALLOT 1 TIME 2 (of 3) ]
    [ time 2 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 0 (of 2) ]
    [ time 2 ] FINISHED JOB 0
    [ time 3 ] Run JOB 1 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 1 (of 3) ]
    [ time 4 ] Run JOB 1 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 0 (of 3) ]
    [ time 4 ] FINISHED JOB 1

    Job StartTime Response Turnaround
    0 0 0 3
    1 0 1 5

    Actually:

    Execution Trace:

[ time 0 ] JOB BEGINS by JOB 0
[ time 0 ] JOB BEGINS by JOB 1
[ time 0 ] Run JOB 0 at PRIORITY 1 [ TICKS 1 ALLOT 1 TIME 1 (of 2) ]
[ time 1 ] Run JOB 0 at PRIORITY 1 [ TICKS 0 ALLOT 1 TIME 0 (of 2) ]
[ time 2 ] FINISHED JOB 0
[ time 2 ] Run JOB 1 at PRIORITY 1 [ TICKS 1 ALLOT 1 TIME 2 (of 3) ]
[ time 3 ] Run JOB 1 at PRIORITY 1 [ TICKS 0 ALLOT 1 TIME 1 (of 3) ]
[ time 4 ] Run JOB 1 at PRIORITY 0 [ TICKS 1 ALLOT 1 TIME 0 (of 3) ]
[ time 5 ] FINISHED JOB 1

Final statistics:
  Job  0: startTime   0 - response   0 - turnaround   2
  Job  1: startTime   0 - response   2 - turnaround   5

  Avg  1: startTime n/a - response 1.00 - turnaround 3.50

    Okay, I made another mistake. I though the unit of allotment is the unit of time. It is actually a whole time segment.
    And the job should be finished at the next time unit.
    Just give me another chance:(And the last one)

    root@C202511211157657:~# python3 mlfq.py -j 2 -M 0 -m 8 -n 2 -q 2 -s 7
Here is the list of inputs:
OPTIONS jobs 2
OPTIONS queues 2
OPTIONS allotments for queue  1 is   1
OPTIONS quantum length for queue  1 is   2
OPTIONS allotments for queue  0 is   1
OPTIONS quantum length for queue  0 is   2
OPTIONS boost 0
OPTIONS ioTime 5
OPTIONS stayAfterIO False
OPTIONS iobump False


For each job, three defining characteristics are given:
  startTime : at what time does the job enter the system
  runTime   : the total CPU time needed by the job to finish
  ioFreq    : every ioFreq time units, the job issues an I/O
              (the I/O takes ioTime units to complete)

Job List:
  Job  0: startTime   0 - runTime   3 - ioFreq   0
  Job  1: startTime   0 - runTime   5 - ioFreq   0

Compute the execution trace for the given workloads.
If you would like, also compute the response and turnaround
times for each of the jobs.

Use the -c flag to get the exact results when you are finished.

    It would be like:
    [ time 0 ] JOB BEGINS by JOB 0
    [ time 0 ] JOB BEGINS by JOB 1
    [ time 0 ] Run JOB 0 at PRIORITY 1 [ TICKS 1 ALLOT 1 TIME 2 (of 3) ]
    [ time 1 ] Run JOB 0 at PRIORITY 1 [ TICKS 0 ALLOT 1 TIME 1 (of 3) ]
    [ time 2 ] Run JOB 1 at PRIORITY 1 [ TICKS 1 ALLOT 1 TIME 4 (of 5) ]
    [ time 3 ] Run JOB 1 at PRIORITY 1 [ TICKS 0 ALLOT 1 TIME 3 (of 5) ]
    [ time 4 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 1 TIME 0 (of 3) ]
    [ time 5 ] FINISHED JOB 0
    [ time 5 ] Run JOB 1 at PRIORITY 0 [ TICKS 1 ALLOT 1 TIME 2 (of 5) ]
    [ time 6 ] Run JOB 1 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 1 (of 5) ]
    [ time 7 ] Run JOB 1 at PRIORITY 0 [ TICKS 1 ALLOT 1 TIME 0 (of 5) ]
    [ time 8 ] FINISHED JOB 1
    | Job | StartTime | Response | Turnaround |
    |———-|———-|———-|———-|
    | 0 | 0 | 0 | 5 |
    | 1 | 0 | 2 | 8 |

    Actually:
    Finally it’s the same as my answer.

    One single long job:

    root@C202511211157657:~# python3 mlfq.py -l 0,40,0 -q 2 -a 2 -c
Here is the list of inputs:
OPTIONS jobs 1
OPTIONS queues 3
OPTIONS allotments for queue  2 is   2
OPTIONS quantum length for queue  2 is   2
OPTIONS allotments for queue  1 is   2
OPTIONS quantum length for queue  1 is   2
OPTIONS allotments for queue  0 is   2
OPTIONS quantum length for queue  0 is   2
OPTIONS boost 0
OPTIONS ioTime 5
OPTIONS stayAfterIO False
OPTIONS iobump False


For each job, three defining characteristics are given:
  startTime : at what time does the job enter the system
  runTime   : the total CPU time needed by the job to finish
  ioFreq    : every ioFreq time units, the job issues an I/O
              (the I/O takes ioTime units to complete)

Job List:
  Job  0: startTime   0 - runTime  40 - ioFreq   0


Execution Trace:

[ time 0 ] JOB BEGINS by JOB 0
[ time 0 ] Run JOB 0 at PRIORITY 2 [ TICKS 1 ALLOT 2 TIME 39 (of 40) ]
[ time 1 ] Run JOB 0 at PRIORITY 2 [ TICKS 0 ALLOT 2 TIME 38 (of 40) ]
[ time 2 ] Run JOB 0 at PRIORITY 2 [ TICKS 1 ALLOT 1 TIME 37 (of 40) ]
[ time 3 ] Run JOB 0 at PRIORITY 2 [ TICKS 0 ALLOT 1 TIME 36 (of 40) ]
[ time 4 ] Run JOB 0 at PRIORITY 1 [ TICKS 1 ALLOT 2 TIME 35 (of 40) ]
[ time 5 ] Run JOB 0 at PRIORITY 1 [ TICKS 0 ALLOT 2 TIME 34 (of 40) ]
[ time 6 ] Run JOB 0 at PRIORITY 1 [ TICKS 1 ALLOT 1 TIME 33 (of 40) ]
[ time 7 ] Run JOB 0 at PRIORITY 1 [ TICKS 0 ALLOT 1 TIME 32 (of 40) ]
[ time 8 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 2 TIME 31 (of 40) ]
[ time 9 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 2 TIME 30 (of 40) ]
...
[ time 39 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 0 (of 40) ]
[ time 40 ] FINISHED JOB 0

Final statistics:
  Job  0: startTime   0 - response   0 - turnaround  40

  Avg  0: startTime n/a - response 0.00 - turnaround 40.00

    Adding a short job:

    root@C202511211157657:~# python3 mlfq.py -l 0,40,0:20,8,0 -q 2 -a 2 -c
Here is the list of inputs:
OPTIONS jobs 2
OPTIONS queues 3
OPTIONS allotments for queue  2 is   2
OPTIONS quantum length for queue  2 is   2
OPTIONS allotments for queue  1 is   2
OPTIONS quantum length for queue  1 is   2
OPTIONS allotments for queue  0 is   2
OPTIONS quantum length for queue  0 is   2
OPTIONS boost 0
OPTIONS ioTime 5
OPTIONS stayAfterIO False
OPTIONS iobump False


For each job, three defining characteristics are given:
  startTime : at what time does the job enter the system
  runTime   : the total CPU time needed by the job to finish
  ioFreq    : every ioFreq time units, the job issues an I/O
              (the I/O takes ioTime units to complete)

Job List:
  Job  0: startTime   0 - runTime  40 - ioFreq   0
  Job  1: startTime  20 - runTime   8 - ioFreq   0


Execution Trace:

[ time 0 ] JOB BEGINS by JOB 0
[ time 0 ] Run JOB 0 at PRIORITY 2 [ TICKS 1 ALLOT 2 TIME 39 (of 40) ]
[ time 1 ] Run JOB 0 at PRIORITY 2 [ TICKS 0 ALLOT 2 TIME 38 (of 40) ]
[ time 2 ] Run JOB 0 at PRIORITY 2 [ TICKS 1 ALLOT 1 TIME 37 (of 40) ]
[ time 3 ] Run JOB 0 at PRIORITY 2 [ TICKS 0 ALLOT 1 TIME 36 (of 40) ]
[ time 4 ] Run JOB 0 at PRIORITY 1 [ TICKS 1 ALLOT 2 TIME 35 (of 40) ]
[ time 5 ] Run JOB 0 at PRIORITY 1 [ TICKS 0 ALLOT 2 TIME 34 (of 40) ]
[ time 6 ] Run JOB 0 at PRIORITY 1 [ TICKS 1 ALLOT 1 TIME 33 (of 40) ]
[ time 7 ] Run JOB 0 at PRIORITY 1 [ TICKS 0 ALLOT 1 TIME 32 (of 40) ]
[ time 8 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 2 TIME 31 (of 40) ]
...
[ time 19 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 20 (of 40) ]
[ time 20 ] JOB BEGINS by JOB 1
[ time 20 ] Run JOB 1 at PRIORITY 2 [ TICKS 1 ALLOT 2 TIME 7 (of 8) ]
[ time 21 ] Run JOB 1 at PRIORITY 2 [ TICKS 0 ALLOT 2 TIME 6 (of 8) ]
[ time 22 ] Run JOB 1 at PRIORITY 2 [ TICKS 1 ALLOT 1 TIME 5 (of 8) ]
[ time 23 ] Run JOB 1 at PRIORITY 2 [ TICKS 0 ALLOT 1 TIME 4 (of 8) ]
[ time 24 ] Run JOB 1 at PRIORITY 1 [ TICKS 1 ALLOT 2 TIME 3 (of 8) ]
[ time 25 ] Run JOB 1 at PRIORITY 1 [ TICKS 0 ALLOT 2 TIME 2 (of 8) ]
[ time 26 ] Run JOB 1 at PRIORITY 1 [ TICKS 1 ALLOT 1 TIME 1 (of 8) ]
[ time 27 ] Run JOB 1 at PRIORITY 1 [ TICKS 0 ALLOT 1 TIME 0 (of 8) ]
[ time 28 ] FINISHED JOB 1
[ time 28 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 2 TIME 19 (of 40) ]
...
[ time 47 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 0 (of 40) ]
[ time 48 ] FINISHED JOB 0

Final statistics:
  Job  0: startTime   0 - response   0 - turnaround  48
  Job  1: startTime  20 - response   0 - turnaround   8

  Avg  1: startTime n/a - response 0.00 - turnaround 28.00

    I/O involved:

    root@C202511211157657:~# python3 mlfq.py -l 0,40,0:5,8,1 -q 2 -a 2 -c
Here is the list of inputs:
OPTIONS jobs 2
OPTIONS queues 3
OPTIONS allotments for queue  2 is   2
OPTIONS quantum length for queue  2 is   2
OPTIONS allotments for queue  1 is   2
OPTIONS quantum length for queue  1 is   2
OPTIONS allotments for queue  0 is   2
OPTIONS quantum length for queue  0 is   2
OPTIONS boost 0
OPTIONS ioTime 5
OPTIONS stayAfterIO False
OPTIONS iobump False


For each job, three defining characteristics are given:
  startTime : at what time does the job enter the system
  runTime   : the total CPU time needed by the job to finish
  ioFreq    : every ioFreq time units, the job issues an I/O
              (the I/O takes ioTime units to complete)

Job List:
  Job  0: startTime   0 - runTime  40 - ioFreq   0
  Job  1: startTime   5 - runTime   8 - ioFreq   1


Execution Trace:

[ time 0 ] JOB BEGINS by JOB 0
[ time 0 ] Run JOB 0 at PRIORITY 2 [ TICKS 1 ALLOT 2 TIME 39 (of 40) ]
[ time 1 ] Run JOB 0 at PRIORITY 2 [ TICKS 0 ALLOT 2 TIME 38 (of 40) ]
[ time 2 ] Run JOB 0 at PRIORITY 2 [ TICKS 1 ALLOT 1 TIME 37 (of 40) ]
[ time 3 ] Run JOB 0 at PRIORITY 2 [ TICKS 0 ALLOT 1 TIME 36 (of 40) ]
[ time 4 ] Run JOB 0 at PRIORITY 1 [ TICKS 1 ALLOT 2 TIME 35 (of 40) ]
[ time 5 ] JOB BEGINS by JOB 1
[ time 5 ] Run JOB 1 at PRIORITY 2 [ TICKS 1 ALLOT 2 TIME 7 (of 8) ]
[ time 6 ] IO_START by JOB 1
IO DONE
[ time 6 ] Run JOB 0 at PRIORITY 1 [ TICKS 0 ALLOT 2 TIME 34 (of 40) ]
[ time 7 ] Run JOB 0 at PRIORITY 1 [ TICKS 1 ALLOT 1 TIME 33 (of 40) ]
[ time 8 ] Run JOB 0 at PRIORITY 1 [ TICKS 0 ALLOT 1 TIME 32 (of 40) ]
[ time 9 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 2 TIME 31 (of 40) ]
[ time 10 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 2 TIME 30 (of 40) ]
[ time 11 ] IO_DONE by JOB 1
[ time 11 ] Run JOB 1 at PRIORITY 2 [ TICKS 0 ALLOT 2 TIME 6 (of 8) ]
[ time 12 ] IO_START by JOB 1
IO DONE
[ time 12 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 1 TIME 29 (of 40) ]
[ time 13 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 28 (of 40) ]
[ time 14 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 2 TIME 27 (of 40) ]
[ time 15 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 2 TIME 26 (of 40) ]
[ time 16 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 1 TIME 25 (of 40) ]
[ time 17 ] IO_DONE by JOB 1
[ time 17 ] Run JOB 1 at PRIORITY 2 [ TICKS 1 ALLOT 1 TIME 5 (of 8) ]
[ time 18 ] IO_START by JOB 1
IO DONE
[ time 18 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 24 (of 40) ]
[ time 19 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 2 TIME 23 (of 40) ]
[ time 20 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 2 TIME 22 (of 40) ]
[ time 21 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 1 TIME 21 (of 40) ]
[ time 22 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 20 (of 40) ]
[ time 23 ] IO_DONE by JOB 1
[ time 23 ] Run JOB 1 at PRIORITY 2 [ TICKS 0 ALLOT 1 TIME 4 (of 8) ]
[ time 24 ] IO_START by JOB 1
IO DONE
[ time 24 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 2 TIME 19 (of 40) ]
[ time 25 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 2 TIME 18 (of 40) ]
[ time 26 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 1 TIME 17 (of 40) ]
[ time 27 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 16 (of 40) ]
[ time 28 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 2 TIME 15 (of 40) ]
[ time 29 ] IO_DONE by JOB 1
[ time 29 ] Run JOB 1 at PRIORITY 1 [ TICKS 1 ALLOT 2 TIME 3 (of 8) ]
[ time 30 ] IO_START by JOB 1
IO DONE
[ time 30 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 2 TIME 14 (of 40) ]
[ time 31 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 1 TIME 13 (of 40) ]
[ time 32 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 12 (of 40) ]
[ time 33 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 2 TIME 11 (of 40) ]
[ time 34 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 2 TIME 10 (of 40) ]
[ time 35 ] IO_DONE by JOB 1
[ time 35 ] Run JOB 1 at PRIORITY 1 [ TICKS 0 ALLOT 2 TIME 2 (of 8) ]
[ time 36 ] IO_START by JOB 1
IO DONE
[ time 36 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 1 TIME 9 (of 40) ]
[ time 37 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 8 (of 40) ]
[ time 38 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 2 TIME 7 (of 40) ]
[ time 39 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 2 TIME 6 (of 40) ]
[ time 40 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 1 TIME 5 (of 40) ]
[ time 41 ] IO_DONE by JOB 1
[ time 41 ] Run JOB 1 at PRIORITY 1 [ TICKS 1 ALLOT 1 TIME 1 (of 8) ]
[ time 42 ] IO_START by JOB 1
IO DONE
[ time 42 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 4 (of 40) ]
[ time 43 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 2 TIME 3 (of 40) ]
[ time 44 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 2 TIME 2 (of 40) ]
[ time 45 ] Run JOB 0 at PRIORITY 0 [ TICKS 1 ALLOT 1 TIME 1 (of 40) ]
[ time 46 ] Run JOB 0 at PRIORITY 0 [ TICKS 0 ALLOT 1 TIME 0 (of 40) ]
[ time 47 ] FINISHED JOB 0
[ time 47 ] IO_DONE by JOB 1
[ time 47 ] Run JOB 1 at PRIORITY 1 [ TICKS 0 ALLOT 1 TIME 0 (of 8) ]
[ time 48 ] FINISHED JOB 1

Final statistics:
  Job  0: startTime   0 - response   0 - turnaround  47
  Job  1: startTime   5 - response   0 - turnaround  43

  Avg  1: startTime n/a - response 0.00 - turnaround 45.00
    1. I thought setting just one queue would work.

    4.Omitted.

    5.10ms / 5% = 200ms.

    6.Omitted.

    Author
    b-a
    Modification

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